电子课本网 第82页

第82页

信息发布者:
C
D
1
-16
9
2
解:​$\begin {cases}3x+\frac {1}{2}y = 8&①\\2x-\frac {1}{2}y = 2&②\end {cases}$​
① + ②,得​$5x = 10,$
​即​$x = 2,$​
​$ $​把​$x = 2$​代入​$①,$​得​
$3×2+\frac {1}{2}y = 8,$​​
​解得​$y = 4,$​
​$ $​所以方程组的解为
​$\begin {cases}x = 2\\y = 4\end {cases}$​
解:​$\begin {cases}x + y = 5&①\\2x + 3y = 11&②\end {cases}$​
​$ ①×3 - ②,$​得
​$x = 4,$​
​$ $​把​$x = 4$​代入​$①,$​得
​$4 + y = 5,$​解得​$y = 1,$​
所以方程组的解为
​$\begin {cases}x = 4\\y = 1\end {cases};$​
解:
​$\begin {cases}2x + 5y = 11&①\\5x + 2y = -4&②\end {cases}$​
​$ ①×5 - ②×2,$​得
​$21y = 63,$​
解得​$y = 3,$​
​$ $​把​$y = 3$​代入​$②,$​得
​$5x + 2×3 = -4,$​
解得​$x = -2,$​
​$ $​所以方程组的解为
​$\begin {cases}x = -2\\y = 3\end {cases}$​
解:由原方程可得
​$\begin {cases}2x + y = 3&①\\2x - y = 5&②\end {cases}$​
 ① + ②,得​$4x = 8,$
​解得​$x = 2,$​
 ① - ②,得​$2y = -2,$
​解得​$y = -1,$​
​$ $​所以方程组的解为
​$\begin {cases}x = 2\\y = -1\end {cases}$​
B
A
-10
3