解:$(1)$∵$∠C=90°,$$∠A=60°$
∴$∠B=90°-∠A=30°$
∴$b=\frac {1}{2}\ \mathrm {c}=\frac {1}{2} ×8 \sqrt{3}=4 \sqrt{3},$$a=c · s in 60°=8 \sqrt{3} × \frac {\sqrt{3}}{2}=12$
∴$∠B=30°,$$a=12,$$b=4 \sqrt{3} $
$(2)$∵$∠C=90°,$$∠A=45°$
∴$∠B=90°-∠A=45°$
∴$a=b=3 \sqrt{6},$$c=\frac {a}{sin 45°} =\frac {a}{\sqrt{2}2} =\sqrt{2}\ \mathrm {a}=\sqrt{2} ×3 \sqrt{6}=6 \sqrt{3}$
∴$∠B=45°,$
$b=3 \sqrt{6},$
$c=6 \sqrt{3}$