$解:何亮的成绩更稳定,理由如下:$
$ \because \overline{x}_{赵明}=\frac {1}{5}\times (25+23+27+29+21)=25(个),$
$\overline{x}_{何亮}=\frac {1}{5}\times (24+25+23+26+27)=25(个),$
$\therefore {S}_{赵明}^2=\frac {1}{5}\times [(25-25)^2+(23-25)^2+\ldots +(21-25)^2]=8,$
${S}_{何亮}^2=\frac {1}{5}\times [(24-25)^2+(25-25)^2+\ldots +(27-25)^2]=2,$
$从方差来看,{S}_{赵明}^2 \gt {S}_{何亮}^2,何亮的成绩更稳定.$