解:由$①$可得$2x-y=2③$
将$③$代入$②$得$\frac {3(2x-y)+4}6+2y=12,$即$\frac {3×2+4}6+2y=12$
∴$\frac {5}{3}+2y=12,$解得$y=\frac {31}{6}$
将$y=\frac {31}{6}$代入$③$得$x=\frac {43}{12}$
∴方程组的解为$\begin {cases}{x=\frac {43}{12}}\\{y=\frac {31}{6}}\end {cases}$