解:$(1)W_{有}=Gh={ 810 }\ \text {N}×{ 1 }\ \text {m}={ 810 }\ \text {J}$
$ (2)W=Pt={ 90 }\ \text {W}×{ 10 }\ \text {s}={ 900 }\ \text {J}$
$ η=\frac {W_{有}}{W}×100\%=\frac {{ 810 }\ \text{J}}{{ 900 }\ \text{J}}×100\%={ 90 }\%$
$ (3)η=\frac {G}{G+G_{动}}$,解得$G_{动}=90\ \text {N}$