解：$(1)R_{ }=\frac {U_{ }}{I_{ }}=\frac {{ 220 }\ \text {V}}{{ 2 }\ \text {A}}={ 110 }Ω$
$ (2)P_{ }=U_{ }I_{ }={ 220 }\ \text{V}×{ 2}\ \text{A}={440 }\ \text{W}$
$ (3)W_{ }=P_{ } t_{ }={ 440 }\ \text {W}×{ 10×60}\ \text {s}={ 2.64×10^5 }\ \text {J}$
